Materials:1). 0.02 mol dm-3 Potassium Manganate2). 0.2 mol dm-3 Glucose3). 2 mol dm-3 sulfuric Acid4). 50 cm3 Burette5). 250 cm3 Beaker6). Measuring Cylinder7). Thermometer (-10 to 110 oC)Hypothesis:By giveing glucose to a settlement of KMnO4 and H2SO4, the solution go away turn colourless and it will push a specific time for the reaction to complete. By change magnitude the temperature, the time it takes (the rate) for the solution to completely change to colourless will be increased. Thus it can be said, that it is being hypothesized that an ?increase in temperature will cause an equal increase in the rate of the reaction?.
Method:1). Using a standard cylinder, place 50 cm3 of sulphuric acid into a 250 cm3 beaker, add 50 cm3 of water using the same measuring cylinder, and then, from a burette, run in 5 cm3 of the potassium manganate (VII) solution. Heat the resulting mix to about 55 oC, stirring gently while heating. derriere a beaker containing the hot solution on a ovalbumin tile or a piece of paper.
2). Noting the time, pour 20 cm3 of the glucose solution (using a measuring cylinder) into the beaker. Swirl and then billhook the temperature. Note the time when the solution turns colourless.
4). Record the results in send back as seen on the proceeding page.
5). Plot a represent of time against temperature (since temperature is the independent variable).
6). Analyze the represent after the set have been plotted. Comment on the line of best forgather and other deductions that can be seen.
7). Plot a graph of concentration of KMnO4 against time and deduce whether the reaction is zero order, commencement order or second order. Take the concentration as 0.02 mol dm-3.
Changing VariablesThe temperature is changed.
Constant VariablesThe amount of glucose solution stay the same.
The volumes of Potassium...
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